Functions CANNOT overload based on the Return Type!

Can a function get overload based on its return type? As follows :- 

class My {
public:
    int get(int);
    char get(int); }

NO! You can't overload methods based on return type!, As mentioned in above snippet.

Overload resolution takes into account the function signature. 

A function signature is made up of:

• function name
• cv-qualifiers
• parameter types

And here's the quote:

1.3.11 signature

the information about a function that participates in overload resolution (13.3): its parameter-type-list (8.3.5) and, if the function is a class member, the cv-qualifiers (if any) on the function itself and the class in which the member function is declared. [...]

Options:

1) change the method name:

class My {
public:
    int getInt(int);
    char getChar(int);
};

2) out parameter:

class My {
public:
    void get(int, int&);
    void get(int, char&);
}

3) templates... overkill in this case.